Cluster ising.py
From Werner KRAUTH
(Difference between revisions)
												
			
			| Revision as of 21:37, 22 September 2015 Werner (Talk | contribs) ← Previous diff | Revision as of 21:50, 22 September 2015 Werner (Talk | contribs) Next diff → | ||
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| - | This page presents the program markov_disks_box.py, a Markov-chain algorithm for four disks in a square box of sides 1. | + | This page presents the program cluster_ising.py, the Wolff cluster algorithm for the Ising model on an LxL square lattice in two dimensions | 
| __FORCETOC__ | __FORCETOC__ | ||
| Line 6: | Line 6: | ||
| =Program= | =Program= | ||
| - | import random | ||
| - | |||
| - | L = [[0.25, 0.25], [0.75, 0.25], [0.25, 0.75], [0.75, 0.75]] | ||
| - | sigma = 0.15 | ||
| - | sigma_sq = sigma ** 2 | ||
| - | delta = 0.1 | ||
| - | n_steps = 1000 | ||
| - | for steps in range(n_steps): | ||
| - | a = random.choice(L) | ||
| - | b = [a[0] + random.uniform(-delta, delta), a[1] + random.uniform(-delta, delta)] | ||
| - | min_dist = min((b[0] - c[0]) ** 2 + (b[1] - c[1]) ** 2 for c in L if c != a) | ||
| - | box_cond = min(b[0], b[1]) < sigma or max(b[0], b[1]) > 1.0 - sigma | ||
| - | if not (box_cond or min_dist < 4.0 * sigma ** 2): | ||
| - | a[:] = b | ||
| - | print L | ||
| - | =Version= | ||
| - | See history for version information. | ||
| - | |||
| - | [[Category:Python]] | ||
| Line 53: | Line 34: | ||
| for j in Cluster: | for j in Cluster: | ||
| S[j] *= -1 | S[j] *= -1 | ||
| + | |||
| + | |||
| + | =Version= | ||
| + | See history for version information. | ||
| + | |||
| + | [[Category:Python]] [[Category:Honnef_2015]] [[Category:MOOC_SMAC]] | ||
Revision as of 21:50, 22 September 2015
This page presents the program cluster_ising.py, the Wolff cluster algorithm for the Ising model on an LxL square lattice in two dimensions
| Contents | 
Description
Program
import random, math
L = 100
N = L * L
nbr = {i : ((i // L) * L + (i + 1) % L, (i + L) % N,
            (i // L) * L + (i - 1) % L, (i - L) % N)
                                    for i in range(N)}
T = 2.5
p  = 1.0 - math.exp(-2.0 / T)
nsteps = 10000
S = [random.choice([1, -1]) for k in range(N)]
for step in range(nsteps):
    k = random.randint(0, N - 1)
    Pocket, Cluster = [k], [k]
    while Pocket != []:
        j = random.choice(Pocket)
        for l in nbr[j]:
            if S[l] == S[j] and l not in Cluster \
                   and random.uniform(0.0, 1.0) < p:
                Pocket.append(l)
                Cluster.append(l)
        Pocket.remove(j)
    for j in Cluster:
        S[j] *= -1
Version
See history for version information.
