Pebble transfer.py
From Werner KRAUTH
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import numpy | import numpy | ||
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neighbor = [[1, 3, 0, 0], [2, 4, 0, 1], [2, 5, 1, 2], | neighbor = [[1, 3, 0, 0], [2, 4, 0, 1], [2, 5, 1, 2], | ||
[4, 6, 3, 0], [5, 7, 3, 1], [5, 8, 4, 2], | [4, 6, 3, 0], [5, 7, 3, 1], [5, 8, 4, 2], |
Revision as of 21:05, 22 September 2015
import numpy neighbor = [[1, 3, 0, 0], [2, 4, 0, 1], [2, 5, 1, 2], [4, 6, 3, 0], [5, 7, 3, 1], [5, 8, 4, 2], [7, 6, 6, 3], [8, 7, 6, 4], [8, 8, 7, 5]] transfer = numpy.zeros((9, 9)) for k in range(9): for neigh in range(4): transfer[neighbor[k][neigh], k] += 0.25 position = numpy.zeros(9) position[8] = 1.0 for t in range(100): print t,' ',["%0.5f" % i for i in position] position = numpy.dot(transfer, position)